C语言编写9*9乘法表出现乱码怎么破

Question

C语言编写9*9乘法表出现乱码怎么破

以下为代码及其结果
#######define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
int main()
{
int n = 9;
int i, j;
i = 1;
while (i <= 9) {
j = 1;
while (j <= i) {
printf("%d*%d=%4d,j,i,ij");
j++;
}
printf("\n");
i++;
}
return 0;
}
就出现这种的
-406016464-406008336=-1244138040,j,i,ij
-775906368-641=-1244138672,j,i,ij-775906368-641=-1244138672,j,i,ij
-775906368-641=-1244138672,j,i,ij-775906368-641=-1244138672,j,i,ij-775906368-641=-1244138672,j,i,ij
-775906368-641=-1244138672,j,i,ij-775906368-641=-1244138672,j,i,ij-775906368-641=-1244138672,j,i,ij-775906368-641=-1244138672,j,i,i*j

Answer 1

并不是什么乱码，是你写错了

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
int main()
{
int n = 9;
int i, j;
i = 1;
while (i <= 9) {
    j = 1;
    while (j <= i) {
        printf("%d*%d=%d\t",j,i,i*j);
        j++;
    }
    printf("\n");
    i++;
}
return 0;
}