执行x的博客三种循环实现等差数列求和 for循环 #include<stdio.h> int Sum(int num) { int result = 0; for (int i = 1; i <= num; ++i) { result += i; } return result; } while循环 #include<stdio.h&...
玖玖!的博客题目描述 sum=2+5+8+11+14+…,输入正整数n,求sum的前n项和。... * 等差数列求和公式Sn=n*a1+n(n-1)d/2或者Sn=n(a1+an)/2 */ int main() { int n; int sum=0; scanf("%d",&n); sum=n*2+n*(n-1)*3/2; pr