如何用正则表达式删除网址中的指定部分

Question

替换前

https://www.123.com/abc/381959786/xyz/2359824672
https://www.123.com/abc/310861904/xyz/2397886336
https://www.123.com/abc/28021901/xyz/2575570645
https://www.123.com/abc/29001914/xyz/2655252812
https://www.123.com/abc/432375183/xyz/2660525016
https://www.123.com/abc/26590963/xyz/2549838667
https://www.123.com/abc/310861904/xyz/2639950518

替换后

https://www.123.com/abc/381959786
https://www.123.com/abc/310861904
https://www.123.com/abc/28021901
https://www.123.com/abc/29001914
https://www.123.com/abc/432375183
https://www.123.com/abc/26590963
https://www.123.com/abc/310861904

也就是查找"/xyz/2397886336"特征结构的文本内容，将其替换为空
我的环境是emeditor编辑器

Answer 1

s为字符串，试试
ret = re.sub(r'/xyz/\d+', "", s)
print(ret)