用python求总和

Question

用python求扑克牌玩二十一点，JKQ都等于10，A是11，但如果总和超过21，A会变成1，比如3
个A和一个6= 19，第一个A是11，后面两个A是1

Answer 1

def blackjack_hand_score(hand):
    anum=0
    score=0
    for i in hand:
        i=i.upper()
        if i.isnumeric():
            score+=int(i)
        elif i=='A':
            anum+=1
        else:
            score+=10
    if anum>0:
        if score + 11 + (anum-1)>21:
            score+=anum
        else:
            score+=11+(anum-1)
            

    return score

hand=['A','K'] 
print('Hand:',hand,'hand score:',blackjack_hand_score(hand))
hand=['A','J','A'] 
print('Hand:',hand,'hand score:',blackjack_hand_score(hand))
hand=['9','8','7'] 
print('Hand:',hand,'hand score:',blackjack_hand_score(hand))
hand=['A','A'] 
print('Hand:',hand,'hand score:',blackjack_hand_score(hand))
hand=['A','A','A','K'] 
print('Hand:',hand,'hand score:',blackjack_hand_score(hand))