Python怎么拆包，并且不同列表迭代？

Question

str = '''
123
abc
+-/
'''
# 转列表
# print：

1a+
1a-
1a/
……

Answer 1

str = '''
123
abc
+-/
'''
arr = [list(x) for x in str.splitlines() if x]
from itertools import product
 
arr = list(product(*arr))

for a in arr:
    print(''.join(a))

输出：
1a+
1a-
1a/
1b+
1b-
1b/
1c+
1c-
1c/
2a+
2a-
2a/
2b+
2b-
2b/
2c+
2c-
2c/
3a+
3a-
3a/
3b+
3b-
3b/
3c+
3c-
3c/

Answer 2

from itertool inport product

Str = "
123
abc
+-/
"
arr = filter(None, Str.splitlines())

Res = map(lambda char : ''.join(char), prpduct(*arr))
print(list(Res))

Answer 3

• 可以看下python参考手册中的 python- 迭代器