dongxia527680 2013-01-20 21:35
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php变量导致while循环在无限循环中显示数据

I'm confused about how these snippets of code differ in displaying results in a while loop. The first snippet of code works perfectly but the second displays the results but does so in an infinite loop and just repeats the results. Can someone explain to me why?

$stmt = $db_conn->prepare($sql);

$stmt->execute(array("Lorna", 3));

while($result = $stmt->fetch()){
    echo $result["name"] . "<br />" . $result["description"] . "<br />";        
}

If I put $stmt->fetch() into a variable called $data and try to pass this instead of just putting $stmt->fetch() in the while loop, I get an infinite loop.

$stmt = $db_conn->prepare($sql);

$stmt->execute(array("Lorna", 3));

$data = $stmt->fetch();

while($result = $data){
    echo $result["name"] . "<br />" . $result["description"] . "<br />";        
}

Thanks in advance!

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3条回答 默认 最新

  • drsvw88664 2013-01-20 21:38
    关注

    If is the call to fetch() which makes the rows advance.

    case 1

    while($result = $stmt->fetch()){
        //every iteration executes fetch
        //advances it by one row
        //turns to false when no more rows
    }
    

    case 2

    $data = $stmt->fetch();
    //now at first row
    while($result = $data){
        //always at first row 
        //always evaluates to true (no calls to fetch)
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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