douzhizao0270 2011-08-18 01:58
浏览 22
已采纳

php条件

I'm having some trouble understanding how PHP parses conditionals.

For instance,

while (list($id, $name, $salary) = mysql_fetch_row($result)) { ...}

(http://php.net/manual/en/function.list.php )

will evaluate true while the list can retrieve values. But printing the list will print the values contained within the list's variables. The manual also says that list() returns an array. How then, does the conditional know that the mysql fetch attempt was successful?

If it does return a boolean, how do you display it directly rather than

if(expr) echo 'true';

thanks!

  • 写回答

1条回答 默认 最新

  • dphfwzn8269 2011-08-18 02:03
    关注

    list() assigns null to the variables listed if assigned a non-array or an array with too few items.

    As null evaluates to false and an array with more than one item evaluates to true, the while loop is able to use the expression.

    Small update

    list() will trigger an "undefined index" E_NOTICE error if the array does not contain enough items

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 微信会员卡等级和折扣规则
  • ¥15 微信公众平台自制会员卡可以通过收款码收款码收款进行自动积分吗
  • ¥15 随身WiFi网络灯亮但是没有网络,如何解决?
  • ¥15 gdf格式的脑电数据如何处理matlab
  • ¥20 重新写的代码替换了之后运行hbuliderx就这样了
  • ¥100 监控抖音用户作品更新可以微信公众号提醒
  • ¥15 UE5 如何可以不渲染HDRIBackdrop背景
  • ¥70 2048小游戏毕设项目
  • ¥20 mysql架构,按照姓名分表
  • ¥15 MATLAB实现区间[a,b]上的Gauss-Legendre积分