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已结题

javascript数据转换

如何把c数组形式的数据转换为a形式的数据?


    let b = [{
    createdAt: '2014-12-21 23:12:00',
    date: '2014-12-24 23:12:00',
    name: `This is production name 1`,
    upgradeNum: 'Upgraded: 56',
    data: {
      name: 'aa',
      platform: 'iOS1',
      version: '10.3.4.5654',
      upgradeNum: 500,
      creator: 'Jack',
    }
  }, {
    createdAt: '2014-12-22 23:12:00',
    date: '2014-12-24 23:12:00',
    name: `This is production name 2`,
    upgradeNum: 'Upgraded: 57',
    data: {
      name: 'aa',
      platform: 'iOS1',
      version: '10.3.4.5654',
      upgradeNum: 500,
      creator: 'Jack',
    }
  }, {
    createdAt: '2014-12-23 23:12:00',
    date: '2014-12-24 23:12:00',
    name: `This is production name 3`,
    upgradeNum: 'Upgraded: 58',
    data: {
      name: 'aa',
      platform: 'iOS1',
      version: '10.3.4.5654',
      upgradeNum: 500,
      creator: 'Jack',
    }
  }, {
    createdAt: '2014-12-11 23:12:00',
    date: '2014-12-24 23:12:00',
    name: `This is production name 1`,
    upgradeNum: 'Upgraded: 1',
    data: {
      name: 'bb',
      platform: 'iOS2',
      version: '10.3.4.5654',
      upgradeNum: 600,
      creator: 'Tom',
    }
  }, {
    createdAt: '2014-12-22 23:12:00',
    date: '2014-12-24 23:12:00',
    name: `This is production name 2`,
    upgradeNum: 'Upgraded: 2',
    data: {
      name: 'bb',
      platform: 'iOS2',
      version: '10.3.4.5654',
      upgradeNum: 600,
      creator: 'Tom',
    }
  }]
  let c = [{
    key:1,
    name: 'aa',
    platform: 'iOS1',
    version: '10.3.4.5654',
    upgradeNum: 500,
    creator: 'Jack',
    children: [{
      key:3,
      createdAt: '2014-12-21 23:12:00',
      date: '2014-12-24 23:12:00',
      name: `This is production name 1`,
      upgradeNum: 'Upgraded: 56',
    }, {
      key:4,
      createdAt: '2014-12-22 23:12:00',
      date: '2014-12-24 23:12:00',
      name: `This is production name 2`,
      upgradeNum: 'Upgraded: 57',
    }, {
      key:5,
      createdAt: '2014-12-23 23:12:00',
      date: '2014-12-24 23:12:00',
      name: `This is production name 3`,
      upgradeNum: 'Upgraded: 58',
    }]
  }, {
    key:2,
    name: 'bb',
    platform: 'iOS2',
    version: '10.3.4.5654',
    upgradeNum: 600,
    creator: 'Tom',
    children: [{
      key:6,
      createdAt: '2014-12-11 23:12:00',
      date: '2014-12-24 23:12:00',
      name: `This is production name 1`,
      upgradeNum: 'Upgraded: 1',
    }, {
      key:7,
      createdAt: '2014-12-22 23:12:00',
      date: '2014-12-24 23:12:00',
      name: `This is production name 2`,
      upgradeNum: 'Upgraded: 2',
    }]
  }]
 
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4条回答 默认 最新

  • CSDN专家-showbo 2022-09-21 09:22
    关注

    上个回复的代码不行吗?json对象中同一个节点中不能出现2个一样的键名称,要不前面的值会被后面的覆盖。
    name: This is production name 1,这个最好换个键名称,比如proName

        let b = [{
            createdAt: '2014-12-21 23:12:00',
            date: '2014-12-24 23:12:00',
            name: `This is production name 1`,
            upgradeNum: 'Upgraded: 56',
            data: {
                name: 'aa',
                platform: 'iOS1',
                version: '10.3.4.5654',
                upgradeNum: 500,
                creator: 'Jack',
            }
        }, {
            createdAt: '2014-12-22 23:12:00',
            date: '2014-12-24 23:12:00',
            name: `This is production name 2`,
            upgradeNum: 'Upgraded: 57',
            data: {
                name: 'aa',
                platform: 'iOS1',
                version: '10.3.4.5654',
                upgradeNum: 500,
                creator: 'Jack',
            }
        }, {
            createdAt: '2014-12-23 23:12:00',
            date: '2014-12-24 23:12:00',
            name: `This is production name 3`,
            upgradeNum: 'Upgraded: 58',
            data: {
                name: 'aa',
                platform: 'iOS1',
                version: '10.3.4.5654',
                upgradeNum: 500,
                creator: 'Jack',
            }
        }, {
            createdAt: '2014-12-11 23:12:00',
            date: '2014-12-24 23:12:00',
            name: `This is production name 1`,
            upgradeNum: 'Upgraded: 1',
            data: {
                name: 'bb',
                platform: 'iOS2',
                version: '10.3.4.5654',
                upgradeNum: 600,
                creator: 'Tom',
            }
        }, {
            createdAt: '2014-12-22 23:12:00',
            date: '2014-12-24 23:12:00',
            name: `This is production name 2`,
            upgradeNum: 'Upgraded: 2',
            data: {
                name: 'bb',
                platform: 'iOS2',
                version: '10.3.4.5654',
                upgradeNum: 600,
                creator: 'Tom',
            }
        }]
        //==========下面为主要代码
        let c = [];
        let keys = Array.from(new Set(b.map(i => i.data.name)));
        let subKeyStart = keys.length + 1;
        keys.forEach((key,index) => {
            let children = b.filter(i => i.data.name == key);
            let cItem = { key: index + 1, ...children[0].data };
            cItem.children = children.map(i => {
                var item = { ...i, key: subKeyStart++ };
                delete item.data;
                return item;
            })
            c.push(cItem);
        });
    
        console.log(c);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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  • 系统已结题 9月29日
  • 已采纳回答 9月21日
  • 修改了问题 9月21日
  • 创建了问题 9月21日

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