需要将多个不通长度的byte[]按顺序合并成一个，请问有什么效率较高的好办法？
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- Json-Huang 2019-09-03 20:08
可以循环遍历byte[]通过System.arraycopy实现，如：
private static byte[] byteMerger(byte[]... byteList) { int lengthByte = 0; for (int i = 0; i < byteList.length; i++) { lengthByte += byteList[i].length; } byte[] allByte = new byte[lengthByte]; int countLength = 0; for (int i = 0; i < byteList.length; i++) { byte[] b = byteList[i]; System.arraycopy(b, 0, allByte, countLength, b.length); countLength += b.length; } return allByte; }赞 踩 打赏 评论分享