问题:请开发一个小小的计算器,当用户输入两整数,计算器可以直接给出和差积商
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qzjhjxj 2022-09-24 20:43关注供参考:
#include <stdio.h> #include <string.h> void plus(double a, double b) { printf("%g + %g = %g\n", a, b, a + b); } void minus(double a, double b) { printf("%g - %g = %g\n", a, b, a - b); } void multiply(double a, double b) { printf("%g * %g = %g\n", a, b, a * b); } void divide(double a, double b) { printf("%g / %g = %.2f\n", a, b, a / b); } int main(void) { int ret; char in[64] = { 0 }, x[16], y[16], op[10]; double a, b;//参加运算的两个数 while (1) { gets(in);//输入算式 if (strcmp(in, "exit") == 0) break; //输入“exit”时,退出计算器 ret = sscanf(in, "%[0-9.] %[^0-9. ] %[0-9.]", x, op, y); if (ret == 3) { sscanf(x, "%lf", &a); sscanf(y, "%lf", &b); if (strcmp(op, "+") == 0) plus(a, b); else if (strcmp(op, "-") == 0) minus(a, b); else if (strcmp(op, "*") == 0) multiply(a, b); else if (strcmp(op, "/") == 0 && b != 0) divide(a, b); else printf("error!Please input again.\n"); } else printf("error!Please input again.\n"); } return 0; }本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报