dqs66973 2015-09-18 06:46
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php中的ldap_add返回“已存在68”错误

I just cannot figure out what I'm doing wrong, I've scoured the web for answers but cannot find anything that works. Please can someone look at my code and tell me where I'm going wrong? If I comment out "objectclass" I get "server is unwilling to perform 53", if I change the OU to something silly (the $dn) then I get "Naming Violation", if I mash the keyboard and put in random letters for the user's name I still get "already exists" error even though no parts of the things I'm entering exist. If I add an ldap_mod_replace line in for another CN in the same OU it works fine so I know the connection is working. I've tried without the '[0]' on all except objectclass too (as I've seen in all examples). Company and user info edited obviously.

$server = "ldap://ServerName.domain.co.uk";
$dn = "OU=Advertising,OU=EmailDepartmentAccounts,OU=Administration,OU=Central,DC=domain,DC=co,DC=uk";

//domain user to connect to LDAP
$user = "helpdesk.ldap@domain.co.uk";
//user password
$psw = "Password";

$ds = ldap_connect($server);
if ($ds) {
    ldap_set_option($ds, LDAP_OPT_PROTOCOL_VERSION, 3);
    ldap_set_option($ds, LDAP_OPT_REFERRALS, 0);
    $r = ldap_bind($ds, $user, $psw);

    $proxyaddresses_array = array();
    $proxyaddresses_array[0] = "X400:c=GB;a= ;p=Company Name p;o=PWEXCHANGE;s=Kitbag;g=Digital;";
    $proxyaddresses_array[1] = "SMTP:test.maff@domain.co.uk";
    $proxyaddresses_array[2] = "smtp:test.maff@other.co.uk";

    //$NewUser = array();
    $NewUser["cn"][0] = "Test Maff1";
    $NewUser["userprincipalname"][0] = "Test.Maff1@domain.co.uk";
    $NewUser["samaccountname"][0] = "Test.Maff";
    $NewUser["objectClass"][0] = "top";
    $NewUser["objectClass"][1] = "person";
    $NewUser["objectClass"][2] = "organizationalPerson";
    $NewUser["objectClass"][3] = "user";
    //$NewUser["givenname"][0] = "Test";
    //$NewUser["sn"][0] = "Maff";
    //$NewUser["instancetype"][0] = 4;
    //$NewUser["physicaldeliveryofficename"][0] = "Leeds";
    //$NewUser["displayname"][0] = "Test Maff";
    //$NewUser["proxyaddresses"] = $proxyaddresses_array;
    //$NewUser["department"][0] = "IT";
    //$NewUser["company"][0] = "Company Name";
    //$NewUser["homemta"][0] = "CN=Microsoft MTA,CN=STH-EXC-01B,CN=Servers,CN=BSP,CN=Administrative Groups,CN=Johnston Press plc,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain,DC=co,DC=uk";
    //$NewUser["displaynameprintable"][0] = "Test Maff";
    //$NewUser["mailnickname"][0] = "Test.Maff";
    //$NewUser["useraccountcontrol"][0] = "512";
    //$NewUser["primarygroupid"][0] = "513";
    //$NewUser["name"] [0]= "Test Maff";
    $NewUser["objectcategory"][0] = "CN=Person,CN=Schema,CN=Configuration,DC=domain,DC=co,DC=uk";
    //$NewUser["mail"] = "Test.Maff@domain.co.uk";

    if ($NewUserAdded = ldap_add($ds, $dn, $NewUser)) {
        echo "success<br />";
    } else {
        echo ldap_error($ds) . " " . ldap_errno($ds);
    }
    ldap_close($ds);
} else {
    echo "unable to connect to LDAP server";
}
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1条回答 默认 最新

  • duanlang1196 2015-09-19 16:52
    关注

    I might be wrong, but from what I read in your code you have an entry OU=Advertising,OU=EmailDepartmentAccounts,OU=Administration,OU=Central,DC=domain,DC=co,DC=uk. And as far as I interpret your code you want to add an entry below that entry. But you have to provide the DN of the new entry as second parameter to ldap_add. But you provide the baseDN of the new entry. and that is already there. Otherwise you wouldn't be able to add something into it.

    So you should call something like the following before calling the ldap_add:

    $dn = 'cn=' . $NewUser['cn'][0] . ',' . $dn;

    That uses the baseDN and prepends it with the cn of the current user.

    Hope that helps

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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