python中如何解套列表提取元组的值

Question

有一个列表a，
a = ["[('Eggs', 6), ('Coffee', 1), ('Pancake', 10), ('Cereal', 5)]",
"[('Coffee', 4), ('Pancake', 9), ('Cereal', 6), ('Eggs', 8)]",
"[('Eggs', 1), ('Coffee', 5), ('Cereal', 7), ('Pancake', 7)]",
"[('Pancake', 3), ('Cereal', 5)]",
"[('Eggs', 3), ('Pancake', 4)]",
"[('Pancake', 1), ('Cereal', 5)]"]

现在想解套列表提取每一个小列表里元祖的第一个值，请问该如何实现呢

Answer 1

代码如下，如果有帮助的话，请点击一下采纳谢谢：

a = ["[('Eggs', 6), ('Coffee', 1), ('Pancake', 10), ('Cereal', 5)]",
"[('Coffee', 4), ('Pancake', 9), ('Cereal', 6), ('Eggs', 8)]",
"[('Eggs', 1), ('Coffee', 5), ('Cereal', 7), ('Pancake', 7)]",
"[('Pancake', 3), ('Cereal', 5)]",
"[('Eggs', 3), ('Pancake', 4)]",
"[('Pancake', 1), ('Cereal', 5)]"]

for temp in a:
    temp = eval(temp)
    for x in temp:
        print(x[0])