python 矩阵运算出问题

Question

NumberOfCandidateDevices = 3
python矩阵运算出问题。 按照代码逻辑， 应该会得到这样的矩阵

#Evaluator1 - Repeatability
#Deviation
Device1_deviation = 0.06 - 0.05
Device2_deviation = 0.06 - 0.05
Device3_deviation = 0.3 - 0.05

DeviceEvaluatorList = []
DeviceEvaluatorList.append(Device1_deviation)
DeviceEvaluatorList.append(Device2_deviation)
DeviceEvaluatorList.append(Device3_deviation)
B =np.empty((NumberOfCandidateDevices,NumberOfCandidateDevices))
for i in range(1, NumberOfCandidateDevices+1):
    for j in range(1, NumberOfCandidateDevices+1):
        a = DeviceEvaluatorList[i-1]
        b = DeviceEvaluatorList[j-1]
        if a < b:
            B[i-1,j-1] = 0.6
        if a == b:
            B[i-1,j-1] = 0.5
        else:
            B[i-1,j-1] = 0
B

但是实际运算出的矩阵如下。即最右边前两行应该为1，但是算出来却为0. 可否解释下原因，并修正下代码

除此之外想把生成 的B 转换成矩阵，如何操作？

Answer 1

赋值的0.6改为1，把最后一个else改为 if a > b:，条件清晰明了，有用记得采纳

import numpy as np

# Evaluator1 - Repeatability
# Deviation
Device1_deviation = 0.06 - 0.05
Device2_deviation = 0.06 - 0.05
Device3_deviation = 0.3 - 0.05
NumberOfCandidateDevices = 3
DeviceEvaluatorList = []

DeviceEvaluatorList.append(Device1_deviation)
DeviceEvaluatorList.append(Device2_deviation)
DeviceEvaluatorList.append(Device3_deviation)
B = np.empty((NumberOfCandidateDevices, NumberOfCandidateDevices))
for i in range(1, NumberOfCandidateDevices + 1):
    for j in range(1, NumberOfCandidateDevices + 1):
        a = DeviceEvaluatorList[i - 1]
        b = DeviceEvaluatorList[j - 1]
        if a < b:
            B[i - 1, j - 1] = 1
        if a == b:
            B[i - 1, j - 1] = 0.5
        if a > b:
            B[i - 1, j - 1] = 0
print(B)