echo 输出结果不对，没有正解引用bool型变量

Question

@echo off&setlocal enabledelayedexpansion

set NameA=true
set NameB=false
set NameC=true
set NameD=true
SET TASK_1_PROJECT_NAME=NameA
SET TASK_2_PROJECT_NAME=NameB
SET TASK_3_PROJECT_NAME=NameC
SET TASK_4_PROJECT_NAME=NameD

for /l %%i in (1, 1, 4) do (
set TempName=!TASK_%%i_PROJECT_NAME!
if !TempName!==true (
echo 'selected'
) else (
echo 'not be selected'
)
)

Answer 1

SET TASK_1_PROJECT_NAME=%NameA%
SET TASK_2_PROJECT_NAME=%NameB%
SET TASK_3_PROJECT_NAME=%NameC%
SET TASK_4_PROJECT_NAME=%NameD%

批处理变量应该这样赋值给另一个变量。