Python 通过方法修改属性的值 无反应

Question

class Car():
def init(self,make,model,year):
self.make = make
self.model = model
self.year = year
self.odometer_reading = 0

def get_descriptive_name(self):
    long_name = str(self.year ) + ' ' + self.make + ' ' +self.model
    return long_name.title()

def read_odometer(self):
    print("This car has " + str(self.odometer_reading) 
    + " miles on it .")
def updat_odometer(self,mileage):
    self.odomter_reading = mileage

my_new_car = Car('audi','a4','2016')
print(my_new_car.get_descriptive_name())

my_new_car.updat_odometer(23) ''''这里实参!放入无反应''
my_new_car.read_odometer()

如果我把 my_new_car.odometer_reading = 23 通过直接修改，不调用updat-odometer()函数就可以生成
This car has 23 miles on it
请问这是为什么？

def 定义函数的位置我改过了了 却没有反应 以下为书上内容

Answer 1

def updat_odometer(self,mileage):
self.odomter_reading = mileage

这句里面的odomter_reading拼写错误了，odom"e"ter。少了个e