duandi8613 2012-03-12 22:18 采纳率: 100%
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将简单的php函数转换为变量

I have a simple function, which I'm trying to turn turn into a query. The idea is to grab the number of facebook likes (which I've done), and pass it into a simple equation (which is ready) to work out the percentage of likes against a target number. I know that the php controling the percentage will return 0.0 at the moment - that's fine for now :) I just can't work out how to get from the function to a variable...

Code as follows:

<?php 
function bfan() {
$pageID = 'VisitTywyn';
$info = json_decode(file_get_contents('http://graph.facebook.com/' . $pageID));
echo $info->likes;
} ?>

<?php bfan(); ?>

<?php
echo number_format(($num_amount/$num_total)*100, 1);
?>

Thanks for your help!

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1条回答 默认 最新

  • donglian3061 2012-03-12 22:21
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    What you want to do is return your result so it can be passed to a variable.

    <?php 
    function bfan() {
    $pageID = 'VisitTywyn';
    $info = json_decode(file_get_contents('http://graph.facebook.com/' . $pageID));
    return $info->likes;
    } ?>
    
    <?php $something = bfan(); ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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