从正则表达式的字符串中获取变量

Question

i'm getting nuts with an regular expression. I have a string like this:

%closed% closed (%closed_percent%\%), %open% open (%open_percent%\%)

What I need is a regular expression that matches the following:

%closed%
%closed_percent%
%open%
%open_percent%

but not the two \%

At the moment I use:

\%([^\%]+)\%

that gives me:

%closed%
%closed_percent%
%), %
% open (%
...

Anyone can help me with that?

Answer 1

The simple way:

%\w+%

Matches: %foo%

Allows (multiple) backslash escapes:

(?<!\\)(?:\\.)*%(\w+)%

Matches only bar in: \%foo% \\%bar% \\\%baz%

...and this allows escapes inside of it too:

(?<!\\)(?:\\.)*%((?:[^\\%\s]+|\\.)+)%

Matches: %foo\%bar%

Use the value of the first capturing group with the last two expressions.