double计算数值时总为1

Question

为什么 当float换为double时 计算结果总为1？

#include <stdio.h>
void main()
{
    int n,i;
float  x,exp = 1.0,s = 1.0,t = 1.0 ,m =1.0;
    printf("请输入 x,n :\n");
    scanf("%f %d",&x,&n);
    for(i = 1; i<=n;i++)
    {
        
        m = m*i;
        s = s*x;
        t = s/m;
        exp = exp + t ;
    }
    printf("%f",exp);
    return ;
}

```c
#include <stdio.h>
void main()
{
    int n,i;
double  x,exp = 1.0,s = 1.0,t = 1.0 ,m =1.0;
    printf("请输入 x,n :\n");
    scanf("%f %d",&x,&n);
    for(i = 1; i<=n;i++)
    {
        
        m = m*i;
        s = s*x;
        t = s/m;
        exp = exp + t ;
    }
    printf("%lf",exp);
    return ;
}

```

Answer 1

27行开头改成scanf("%lf