duanmao1872
2018-03-04 13:21 阅读 57
已采纳

仅在最后一条评论上爆炸,跳过#inside变量

A sample values like this:

fdsfsf345#3gt#$%3^#$T$#tr43r43
test spaces
"test spaces"

"fdsfsf345#3gt#$%3^#$T$#tr43r43" #comment
"test spaces" #comment

A script:

$re = '/(.*)(?:\"|\'|)(?: )#?(.*)|(.*)/mi';
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
var_dump($matches);

A problem is that a line without '# comment' prints

A result should be on first array:

fdsfsf345#3gt#$%3^#$T$#tr43r43
test spaces
"test spaces"

"fdsfsf345#3gt#$%3^#$T$#tr43r43"
"test spaces"

https://regex101.com/r/IpcEPU/1

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2条回答 默认 最新

  • 已采纳
    dousu8456 dousu8456 2018-03-04 23:33

    Given your sample input, you only need to remove substrings from space-hash to the end of the line.

    Code: (Demo)

    $array = [
        'bar',
        'fdsfsf345#3gt#$%3^#$T$#tr43r43',
        'test spaces',
        '"test spaces"',
        '"fdsfsf345#3gt#$%3^#$T$#tr43r43" #comment',
        'test spaces" #comment',
        'bar',
        '""',
        '""""',
        'foo1 #comment2',
        '"with space value" #comment',
        'with quote value\'',
        'somestringstart',
        'with spaces" # a comment',
        'bar'
    ];
    
    $result=preg_replace('~ #.*~','',$array);
    var_export($result);
    

    If you may have space-hash substrings inside of your quoted text, then (*SKIP)(*FAIL) will help by disqualifying these values.

    Pattern: '~(["']).*?\1(*SKIP)(*FAIL)| #.*~' Replace: '' (empty string)

    This will ensure that single or double quote-wrapped space-hash substrings are not matched/removed.

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  • download1214 download1214 2018-03-04 19:56

    Found a solution with regex:

    /(?=(^(.*)[ ])(?=#[ a-z0-9]+))|(?=(^(.*))+)/i
    

    It will parse only values and skip with any type comments.

    https://regex101.com/r/dFVhjr/1

    If have any improved idea it will be welcome.

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