MySQL使用变量准备语句

Question

I am using below PHP + MySQL prepare statement to select values from database, passing the variable into the statement using function, however I could not get my wanted result. The problem is I don't know how to using the variable in the prepare statement.

Question: Could you take a look whether the syntax I am using is correct?

public function getToken($committeeValue){
    $stmt = $this->conn->prepare("SELECT u.token FROM users u INNER JOIN committee c ON u.email = c.email WHERE c.'$committeeValue' = 1");
    $stmt->execute();
}

Answer 1

Please try the below one.   

 public function getToken($committeeValue){
        $stmt = $this->conn->prepare("SELECT u.token FROM users u INNER JOIN committee c ON u.email = c.email WHERE c.".$committeeValue." = 1");
        $stmt->execute();
    }

I think you are made a mistake to appending a php variable within the string.Please try this.