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dongling4288 2016-02-01 03:39
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检查从preg_replace()返回的值是否存在于数组中

I have one message string e.g:

$data="Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";

and I have smile array(for checking)

$smileys=array("laugh","mmmm","smile");

yesterday friends helped me and I convert :smile: type to enter image description here like down

$data=preg_replace("/:([a-zA-Z]+):/","<img src='images/smileys/$1.png' class='smile'>",$data);

and how can I check this smile exists or no in array?

example: http://masters.az
login:test
pass:test
code example:http://masters.az/message-3

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  • dongtai419309 2016-02-01 05:11
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    I would implode the terms with an or then use the found term in the replace.

    $data = "Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";
    $smileys = array("laugh","mmmm","smile");
    echo preg_replace('/:(' . implode('|', $smileys) . '):/', '<img src="images/smileys/$1.png" class="$1">', $data);
    

    PHP Demo: https://eval.in/511095

    Regex101 Demo: https://regex101.com/r/hI1aX0/1

    Here's a JS approach:

    var test = ["laugh","mmmm","smile"];
    var regex = new RegExp(':(' + test.join('|') + '):', 'g');
    var string = "Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";
    var string = string.replace(regex, '<img src="images/smileys/$1.png" class="$1">');
    console.log(string);
    console.log(regex);
    

    Demo: https://jsfiddle.net/8fj00bg5/

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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