QT监测键盘时间 有延迟 在第一次按下按键的时候会有延迟,想要像游戏一样把按键响应做的很丝滑该怎么做嘞
1条回答 默认 最新
- MMMoyier 2022-10-18 11:08关注
emmmmmm 我自己找到了一种解决办法
```c++ #include "dialog.h" #include "ui_dialog.h" Dialog::Dialog(QWidget *parent) : QDialog(parent), ui(new Ui::Dialog) { ui->setupUi(this); this->timer = new QTimer(this); timer->setSingleShot(false); timer->setInterval(10); connect(timer,SIGNAL(timeout()),this,SLOT(timerTimeOutSLot())); timer->start(); } Dialog::~Dialog() { delete ui; } void Dialog::keyPressEvent(QKeyEvent* event) { int key = event->key(); //timer->start(); if(key == Qt::Key_A ){ ui->label_A->setText("A"); this->keyA = true; }else if(key == Qt::Key_S){ ui->label_S->setText("S"); this->keyS = true; }else if(key == Qt::Key_W){ ui->label_w->setText("W"); this->keyW = true; }else if(key == Qt::Key_D){ ui->label_D->setText("D"); this->keyD = true; } } void Dialog::keyReleaseEvent(QKeyEvent *event) { int key = event->key(); if(key == Qt::Key_A ){ ui->label_A->setText("A"); this->keyA = false; }else if(key == Qt::Key_S){ ui->label_S->setText("S"); this->keyS = false; }else if(key == Qt::Key_W){ ui->label_w->setText("W"); this->keyW = false; }else if(key == Qt::Key_D){ ui->label_D->setText("D"); this->keyD = false; } } void Dialog::timerTimeOutSLot() { if(keyA){ ui->pushButton->move(ui->pushButton->x()-2,ui->pushButton->y()); } if(keyS){ ui->pushButton->move(ui->pushButton->x(),ui->pushButton->y()+2); } if(keyW){ ui->pushButton->move(ui->pushButton->x(),ui->pushButton->y()-2); } if(keyD){ ui->pushButton->move(ui->pushButton->x()+2,ui->pushButton->y()); } } //void Dialog::btnClickedSlot() //{ // qDebug()<<"001"; //}
```
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