C语言编程结果输出一直是0怎么办

Question

C语言编程结果输出一直是0应该怎么办

源代码如下：
#include <stdio.h>
#include <stdlib.h>

int main()
{
char car;
long int startingtimehour,startingtimeminute,endingtimehour,endingtimeminute,thetime;
double money;
printf("请输入车辆类型（C代表轿车，B代表客车，T代表卡车)");
car=getchar();
printf("入库:xx时xx分,出库:xx时xx分(请输入对应的数字)");
scanf("四个%ld（因为社区不让输入重复的符号所以只能这样写了）",&startingtimehour,&startingtimeminute,&endingtimehour,&endingtimeminute);
if (endingtimehour=startingtimehour)
{thetime=(endingtimehour-startingtimehour)+(endingtimeminute-startingtimeminute)/60;}
else if (endingtimehour>startingtimehour&&endingtimeminute<=startingtimeminute)
{ if (endingtimehour-startingtimehour==1)
{thetime=(60-(startingtimeminute-endingtimeminute))/60;}
else
{
thetime=(endingtimehour-startingtimehour-1)+(60-(startingtimeminute-endingtimeminute))/60;
}
}
else if(endingtimehour>startingtimehour&&endingtimeminute>startingtimeminute)
{
thetime=(endingtimehour-startingtimehour)+(endingtimeminute-startingtimeminute)/60;
}
else if(endingtimehour<startingtimehour&&endingtimeminute>=startingtimeminute)
{
thetime=(24+endingtimehour-startingtimehour)+(endingtimeminute-startingtimeminute)/60;
}
else
{
if(24+endingtimehour-startingtimehour==1)
{
thetime=(60-(startingtimeminute-endingtimeminute))/60;
}
else
{thetime=(24+endingtimehour-startingtimehour-1)+(60-(startingtimeminute-endingtimeminute))/60;
}
}

switch(car){
    case'C':switch(thetime/3){
              case 0:money=5*thetime;
              c=double money
                     printf("应交%d元\n",money);break;
              case !0:money=5*3+10*(thetime-3);
                      printf("应交%d元\n",money);break; };break;
    case'B':switch(thetime/2){
            case 0:money=10*thetime;
                   printf("应交%d元\n",money);break;
            case !0:money=20+15*(thetime-2);
                   printf("应交%d元\n",money);break;};break;
    case'T':switch(thetime/1){
             case 0:money=10*thetime;
                     printf("应交%d元\n",money);break;
             case !0:money=10+(thetime-1)*15;
                     printf("应交%d元\n",money);break;};break;
                     }

}

这个程序是算三种车的停车费用：输入的是车辆类型和入库出库时间，每一种车辆不同的时间范围内的每小时的收费不一样，输出应交的停车费
最后算停车费结果显示是0
希望有人能指点一下

Answer 1

错误太多，代码也太复杂。完整题目贴出来给你重写一个

Answer 2

if (endingtimehour=startingtimehour) 里面是两个 == 号
还有 case !0: 最好改一下，1就是1，2就是2，不要写这种模糊的表达式，如果有一个case 0，然后就是其他，可直接改成 default:

Answer 3

停车收费系统(C语言作业) - 百度文库

Answer 4

你这前面计算thetime的逻辑写的啥呀，自己把思路理理清楚了再写程序

Answer 5

#include <stdio.h>
int main()
{
  char car;
  long int startingtimehour, startingtimeminute, endingtimehour, endingtimeminute, thetime;
  double hour, money;
  printf("请输入车辆类型（C代表轿车，B代表客车，T代表卡车)");
  car = getchar();
  printf("入库:xx时xx分,出库:xx时xx分(请输入对应的数字)");
  scanf("%ld%ld%ld%ld", &startingtimehour, &startingtimeminute, &endingtimehour, &endingtimeminute);
  thetime = (endingtimehour * 60 + endingtimeminute) - (startingtimehour * 60 + startingtimeminute);
  if (thetime < 0) thetime = 24 * 60 + thetime; //第二天出库
  hour = thetime / 60.0; //转为小时

  switch (car) {
  case 'C':
    if (hour < 3)
      money = 5 * (int)hour; //自行决定 hour 前面是否取整
    else
      money = 5 * 3 + (int)(hour - 3) * 10;
    break;
  case 'B':
    if (hour < 2)
      money = 10 * (int)hour;
    else
      money = 10 * 2 + (int)(hour - 2) * 15;
    break;
  case 'T':
    if (hour < 1)
      money = 10 * (int)hour;
    else
      money = 10 + (int)(hour - 1) * 15;
    break;

  }
  printf("应交%lf元\n", money);
  return 0;
}