C语言编程结果输出一直是0怎么办

C语言编程结果输出一直是0应该怎么办

源代码如下：
#include <stdio.h>
#include <stdlib.h>

int main()
{
char car;
long int startingtimehour,startingtimeminute,endingtimehour,endingtimeminute,thetime;
double money;
printf("请输入车辆类型（C代表轿车，B代表客车，T代表卡车)");
car=getchar();
printf("入库:xx时xx分,出库:xx时xx分(请输入对应的数字)");
scanf("四个%ld（因为社区不让输入重复的符号所以只能这样写了）",&startingtimehour,&startingtimeminute,&endingtimehour,&endingtimeminute);
if (endingtimehour=startingtimehour)
{thetime=(endingtimehour-startingtimehour)+(endingtimeminute-startingtimeminute)/60;}
else if (endingtimehour>startingtimehour&&endingtimeminute<=startingtimeminute)
{ if (endingtimehour-startingtimehour==1)
{thetime=(60-(startingtimeminute-endingtimeminute))/60;}
else
{
thetime=(endingtimehour-startingtimehour-1)+(60-(startingtimeminute-endingtimeminute))/60;
}
}
else if(endingtimehour>startingtimehour&&endingtimeminute>startingtimeminute)
{
thetime=(endingtimehour-startingtimehour)+(endingtimeminute-startingtimeminute)/60;
}
else if(endingtimehour<startingtimehour&&endingtimeminute>=startingtimeminute)
{
thetime=(24+endingtimehour-startingtimehour)+(endingtimeminute-startingtimeminute)/60;
}
else
{
if(24+endingtimehour-startingtimehour==1)
{
thetime=(60-(startingtimeminute-endingtimeminute))/60;
}
else
{thetime=(24+endingtimehour-startingtimehour-1)+(60-(startingtimeminute-endingtimeminute))/60;
}
}

switch(car){
    case'C':switch(thetime/3){
              case 0:money=5*thetime;
              c=double money
                     printf("应交%d元\n",money);break;
              case !0:money=5*3+10*(thetime-3);
                      printf("应交%d元\n",money);break; };break;
    case'B':switch(thetime/2){
            case 0:money=10*thetime;
                   printf("应交%d元\n",money);break;
            case !0:money=20+15*(thetime-2);
                   printf("应交%d元\n",money);break;};break;
    case'T':switch(thetime/1){
             case 0:money=10*thetime;
                     printf("应交%d元\n",money);break;
             case !0:money=10+(thetime-1)*15;
                     printf("应交%d元\n",money);break;};break;
                     }