这段代码有什么算法问题吗？

Question

public void onhq(View view)
    {
        EditText edittext = (EditText) findViewById(R.id.lbm);
        String lbm = edittext.getText() + "";
        if (lbm == password)
        {
            if (libaoma != true)
            {
                TextView textview = (TextView) findViewById(R.id.yn);
                textview.setText("领取成功");
                dj = dj * 10;
                sj = sj + 10 * 100;
            }
            else
            {
                TextView textView = (TextView) findViewById(R.id.yn);
                textView.setText("已经领取过了");
            }
        }
        else
        {
            TextView TextView = (TextView) findViewById(R.id.yn);
            TextView.setText(lbm);
        }
    }
}

Answer 1

字符串类型的比较像等要用equals
所以
if (lbm == password)
要改成
if (lbm.equals(password))