douci1196 2012-07-22 06:12
浏览 98
已采纳

FILTER_VALIDATE_EMAIL无效

I certainly must be missing something here. For some reason filter_var is not working. I'm trying to validate an email from $_POST, and it returns false even with valid emails. But, when I hardcode an email, it works fine. What's wrong?

Here's my php code:

function redirect() { //redirecting to home page function. Used in one of the lectures.
    $host = $_SERVER["HTTP_HOST"]; 
    $path = rtrim(dirname($_SERVER["PHP_SELF"]), "/\\");
    header("Location: http://$host$path/index.php");
    exit;
}

try 
{
    $dbh = new PDO($db, $dbuser, $dbpassword);
}
catch (PDOException $e) 
{
    echo "Connection failure: " . $e->getmessage();
}

if (!isset($_POST['email']) || !isset($_POST['password1']) || !isset($_POST['password2'])) {
    redirect();
}

$password1 = htmlspecialchars($_POST['password1']);
$email = htmlspecialchars($_POST['email']);
$password2 = htmlspecialchars($_POST['password2']);
//preg_match('/.+@.+\./', $email) == FALSE



if ($email = "") {
    print "email not there";

} elseif (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
    print "not real email";

} elseif (strlen($password1) < 6) {
    print("password too small");

}  elseif (!(preg_match('/[A-Za-z].*[0-9]|[0-9].*[A-Za-z]/', $password1))) {
    print "numbers and letters plz";

} elseif ($password1 != $password2) {
    print "passwords not same";
    //redirect();
}
  • 写回答

1条回答 默认 最新

  • dongtun1209 2012-07-22 06:25
    关注

    Change the first email check:

    if ($email == "") {
        print "email not there";
    }
    

    It is getting the value " instead of checking for it.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 如何用stata画出文献中常见的安慰剂检验图
  • ¥15 c语言链表结构体数据插入
  • ¥40 使用MATLAB解答线性代数问题
  • ¥15 COCOS的问题COCOS的问题
  • ¥15 FPGA-SRIO初始化失败
  • ¥15 MapReduce实现倒排索引失败
  • ¥15 ZABBIX6.0L连接数据库报错,如何解决?(操作系统-centos)
  • ¥15 找一位技术过硬的游戏pj程序员
  • ¥15 matlab生成电测深三层曲线模型代码
  • ¥50 随机森林与房贷信用风险模型