没有匹配 if 的非法 else，请求解答

Question

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>

int main()

{
int arr[] = { 1,2,3,4,5,6,7,8,9,10 };
int k = 7;

int sz = sizeof(arr) / sizeof(arr[0]);
int left = 0;
int right = sz - 1;

while(left<=right)

{
int mid = (left + right) / 2;
if (arr[mid] > k);
{
right = mid - 1;
}
else if (arr[mid] < k)

    {
        left = mid + 1;
    }
    else
    {
    printf("找到了,下标是:%d\n", mid);
    break;
   }
}
if (left > right)
{
    printf("找不到\n");
}
return 0;

}

报错：1>D:\code\Project2\Project2\test_4.c(21,3): error C2181: 没有匹配 if 的非法 else

Answer 1

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