使用DateTime :: createFromFormat验证Year

Question

I have this block of code for validating a correctly formatted date prior to submission to a DB insert using DateTime::createFromFormat(). I'm expecting the date format to convert 'DD/MM/YYYY' to 'YYYY-MM-DD' or else raise an error.

$dateofbirth = trim($_POST['dateofbirth']);
$date = DateTime::createFromFormat('d/m/Y', $dateofbirth);

$date_errors = DateTime::getLastErrors();
    var_dump($date_errors);
if ($date_errors['warning_count'] + $date_errors['error_count'] > 0) {
    $dobError = 'Date '.$dateofbirth.' is not a valid DD/MM/YYYY format.';
    $hasError = true;
} else {
    $mysql_dob = $date->format('Y-m-d');
}
error_log($dateofbirth.' -> '.$mysql_dob);

This date works

 $dateofbirth = '30/11/1980'; => 1980-11-30

but this one fail silently

 $dateofbirth = '30/11/80'; => 0080-11-30

since i'm expecting to be notified of the missing century digits. I've read the formatting rules and am using the upper case 'Y' which should ensure a 4 digit year. Any idea's where i'm going wrong?

EDIT

1 - Correct the test date as per OneTrickPony's comment

2 - I added a var_dump of the $date_errors variable. Since the format is 'd/m/Y' and the input is '30/11/80' i am expecting an error or warning but i don't get one.

array(4) {
  ["warning_count"]=>
  int(0)
  ["warnings"]=>
  array(0) {
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
}
30/11/80 -> 0080-11-30

Answer 1

From the documentation for DateTime::createFromFormat

http://www.php.net/manual/en/datetime.createfromformat.php

Returns a new DateTime instance or FALSE on failure.

So rather than checking getLastErrors you should check if $date === false

Change your error check to:

if ($date === false) {
    $dobError = 'Date '.$dateofbirth.' is not a valid DD/MM/YYYY format.';
    $hasError = true;
} else {
    $mysql_dob = $date->format('Y-m-d');
}