日复一日 - C/C++ 类与抽象

Question

有关日复一日-类与抽象的问题，希望大家进行解答（较难，慎重作答）

Answer 1

#include
#include
#include <assert.h>
using namespace std;
class Date{
private:
int year;
int month;
int day;
public:
bool isLeapYear(int year){
//四年一闰，百年不闰，四百年又闰
if (year%400==0)
return true;
else if (year%100==0)
return false;
else if (year%4==0)
return true;
else
return false;
}
Date(const int& y=0,const int& m=0,const int& d=0){
year=y;
month=m;
day=d;
}
string toText(){
char buffer[1024];
sprintf(buffer,"%d-%d-%d",year,month,day);
return buffer;
}
Date nextDay(){
Date d;
d.month=month;
d.year=year;
d.day=day;
if(d.month==2){
if(d.day==29){
d.day=1;d.month++;
}
else if(d.day==28){
if(isLeapYear(d.year)==true){
d.day++;
}
else{
d.day=1;d.month=3;
}
}
else{
d.day++;
}
}
else if(d.month==4||d.month==6||d.month==9||d.month==11){
if(d.day==30){
d.day=1;d.month++;
}
else d.day++;
}
else if(d.month==12){
if(d.day==31){
d.day=1;d.month=1;d.year++;
}
else d.day++;
}
else{
if(d.day==31){
d.day=1;d.month++;
}
else d.day++;
}
return d;
}
Date prevDay(){
Date d;
d.month=month;
d.year=year;
d.day=day;
if(d.month==3){
if(d.day==1){
if(isLeapYear(d.year)==true){
d.day=29;d.month=2;
}
else{
d.day=28;d.month=2;
}
}
else{
d.day--;
}
}
else if(d.month==5||d.month==7||d.month==10||d.month==12){
if(d.day==1){
d.day=30;d.month--;
}
else d.day--;
}
else if(d.month==1){
if(d.day==1){
d.day=31;d.month=12;d.year--;
}
else d.day--;
}
else{
if(d.day==1){
d.day=31;d.month--;
}
else d.day--;
}
return d;
}
};
int main()
{
int year=2000,month=1,day=1;
cin >> year >> month >> day;
Date d(year,month,day);
cout << "Date: " << d.toText() << ", Next Day: " << d.nextDay().toText()
<< ", Prev Day: " << d.prevDay().toText();
return 0;
}