C语言怎么编可中断取反流水灯

Question

用P1口做输出口，接八只发光二极管。编写程序，使发光二极管循环点亮，循环点亮时间间隔为1秒，该时间间隔用定时器中断实现。/ INT0 接单次脉冲输出，每当有外部中断信号时，发光二极管循环方向取反。 请问用C语言怎么编？

Answer 1

仿真如下：

上传不了仿真动图，直接看代码吧

// 12MHz晶振
#include "reg52.h"
#include "intrins.h"

#define time (65536-50000) // 单次定时50ms
unsigned char cn;
unsigned char temp;
unsigned char dir;

void main(void)
{
      cn=20; //20*50ms=1s
      temp=0x80;
      dir=0;
    TMOD = 0x10;                    //set timer1 as mode1 (16-bit)
    TL1 = time;                     //initial timer1 low byte
    TH1 = time >> 8;                //initial timer1 high byte
    TR1 = 1;                        //timer1 start running
    ET1 = 1;                        //enable timer1 interrupt
      IT0 = 1;                        //set INT0 int type (1:Falling 0:Low level)
    EX0 = 1;                        //enable INT0 interrupt
    EA = 1;                         //open global interrupt switch
    
      while(1);// xunhuan

}

/* Timer0 interrupt routine */
void tm1_isr() interrupt 3
{
    TL1 = time;                    
    TH1 = time >> 8;               
    if (cn-- == 0)               
    {
        cn = 20;  
              P1=temp;
              if(dir==0)
          temp=_cror_(temp,1);    
        else
                    temp=_crol_(temp,1);    
    }
}

//External interrupt0 service routine
void exint0() interrupt 0           //(location at 0003H)
{
    dir=~dir;
}