#include
int main(void)
{
int M,N,i;
scanf("%d\n",&M);

while((M--)!=0)
{
while(scanf("%d ",&N),N)
{
int sum =0;
while((N--)!=0)
{
scanf("%d ",&i);
sum +=i;
}if(M !=1){
printf("%d\n\n",sum);
}
else
{ printf("%d\n",sum);
break;
}

}
}

return 0;
}

Problem Description

Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.

Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.

Sample Input
3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3

Sample Output
10

15

6

1个回答

``````
#include <stdio.h>
#include<iostream>
#include <malloc.h>
#include <string.h>

using namespace std;

int main(void)
{
int M,N,item,sum;
scanf("%d",&N);

int *p_sum = (int *)malloc(N*sizeof(int));
memset(p_sum,0x0,N*sizeof(int));
for(int i=0;i<N;i++)
{
sum = 0;
scanf("%d",&M);
while((M--)!=0)
{
scanf("%d",&item);
sum += item;
}
*(p_sum+i) = sum;
}

printf("######Output######\n");
for(int j=0;j<N;j++)
{
printf("%d\n",p_sum[j]);
}

return 0;
}

``````