从键盘输入不超过10行10列的整型二维数组的各元素，求出各奇数行（下标为0,2,4,6...的行，即第1,3,5,7...行）之和， 并把和的每位数字转成拼音输出，各数拼音之间以一个空格分隔。

Question

样例输入：
5 6
56 78 36 4 50 80
19 44 95 72 -8 60
85 67 -3 32 12 35
29 21 47 88 28 -9
7 66 53 40 20 15
样例输出：
304:san ling si
228:er er ba
201:er ling yi
样例说明：
输入5行6列二维数组；分别求出第1,3,5行的和304, 228, 201，
并转换成拼音输出。

#include<stdio.h>
#define N 10
int main()
{
    int a[N][N],i,j,m,n,sum=0,x,k;
    char s[N][N]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    scanf("%d%d",&m,&n);
    for(i=0;i<m;i++)
        for(j=0;j<n;j++)
        scanf("%d",&a[i][j]);
    for(i=0;i<m;i=i+2)
    {
        for(j=0;j<n;j++)
            sum=sum+a[i][j];
        printf("%d:\n",sum);
        sum=0;
    }
    return 0;
}

怎么把拼音加到数字后面

Answer 1

题主代码修改如下，供参考：

#include <stdio.h>
#define N 10
int main()
{
    int   a[N][N],i,j,m,n,sum=0,x[10],k;
    char* s[N]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    scanf("%d%d",&m,&n);
    for(i=0;i<m;i++)
        for(j=0;j<n;j++)
            scanf("%d",&a[i][j]);

    for(i=0;i<m;i+=2)
    {
        for(j=0,sum=0;j<n;j++)
            sum += a[i][j];
        printf("%d:",sum);
        k = 0; x[0]=0;
        while(sum){
            x[k++] = sum % 10;
            sum /= 10;
        }
        if(k == 0) k++;  //当sum为0时 输出 ling
        for(k--;k >= 0;k--)
            printf("%s ",s[x[k]]);
        printf("\n");
    }
    return 0;
}