将php变量作为隐藏输入传递，其中html包含在一个echo中

Question

I'm new with PHP and still learning.

<?php
if(isset($_POST['btnLogin'])){
    $myVariable = $_POST['fieldParameter'];

    if(condition){
        //do something
    }else{

      echo "  
        <form method='POST' action='submit.php'><br/>       
          <input type='hidden' name='myVariable' value='<?php echo $myVariable; ?>'/>
          <br/>
          <input type='submit' name='btnSubmit' id='submit' value='Submit'>
        </form>

          ";
        }
}
?>

Notice that the variable $myVariable is contained in the main IF block. I'm trying to send the value of $myVariable to submit.php as hidden field.

Also, i enclosed all the html tags using one echo statement with double quotes.

I found related questions here in SO but can't find similar to embedding php within a long echo of html tags

I tried to put value='<?php echo $studentNo; ?>' with no success.

I want to access it in a submit.php file like this,

submit.php

<?php 
    $aVariable = $_POST['myVariable'];
    echo $aVariable;
?>

How can I pass the value contained in $myVariable as hidden field? Is there something wrong with the way I use double and single quotes?

Thank you.

Answer 1

You just need to type $myVariable instead of in your string. Double quotes "" only creates a string literal. It doesn't directly output data like inline HTML. As you can see from the syntax coloring in StackOverflow, the

You can try these variants (simplified):

// code before
echo "<input type='hidden' name='myVariable' value='$myVariable'/>";
// code after

// OR //

// code before
?>
<input type='hidden' name='myVariable' value='<?= $myVariable ?>'/>
<?php
// code after

Note that the quotes you use in HTML don't affect PHP, as long as you escape them properly (use \" and \' where appropriate).