dpxpz37157 2014-11-15 08:26
浏览 90
已采纳

如何只在文本输入框中运行php代码

I have a database that I am searching and displaying results from, each php query is in its own file being called by using require_once(ect) in the body.

They are all linked to the same submit button but I would like to only run the one that has text entered into it.

So I have 4 search box's each with there own file like this, which just searches a different column in the database.

I am wanting to only display 'no results found' or the amount of results found if the user has typed anything into that search box and submitted.

What is happening is the code is working but i get the other 3 'no results found' from the other files even though the user has not tried to search in that field.

I feel like there is an easy solution but I just cant figure it out, thanks in advance.

<?php

$stmtArtist = $mysqli->prepare("SELECT artist, genre, event, venue, eventdate FROM events WHERE artist = ?");
$stmtArtist->bind_param('s', $_GET['searchArtist']);
$stmtArtist->execute(); 
$stmtArtist->bind_result($artist, $genre, $event, $venue, $eventdate); 
$stmtArtist->store_result();
$numRows = $stmtArtist->num_rows;

if (isset($_GET['submit'])) {

    if ($numRows <= 0) {

        echo "no results found!";

    } else {

        echo "$numRows "." results found";

        while ($stmtArtist->fetch()) { 
            $timestampDate = strtotime($eventdate);
            $displayDate = date("D d M Y", $timestampDate);

            echo "<table border=1>"; 
            echo "<tr> <th>Artist</th> <th>Genre</th> <th>Venue</th> <th>Date</th> <th>Event</th> </tr>";
            echo "<tr> <td>$artist</td> <td>$genre</td> <td>$venue</td> <td>$eventdate</td> <td>$event</td></tr>";
            echo "</table>";

        }
    }
}
?>

展开全部

  • 写回答

2条回答 默认 最新

  • douwu3763 2014-11-15 08:29
    关注

    Try to actually process the form when you have submitted and it has entered a value:

    <?php
    if (isset($_GET['submit']) && !empty($_GET['searchArtist'])) {
    
        $stmtArtist = $mysqli->prepare("SELECT artist, genre, event, venue, eventdate FROM events WHERE artist = ?");
        $stmtArtist->bind_param('s', $_GET['searchArtist']);
        $stmtArtist->execute(); 
        $stmtArtist->bind_result($artist, $genre, $event, $venue, $eventdate); 
        $stmtArtist->store_result();
    
        $numRows = $stmtArtist->num_rows;
    
        if ($numRows <= 0) {
            echo "no results found!";
        } else {
            echo "$numRows results found <br/>";
    
            echo "<table border=1>"; 
            echo "<tr> <th>Artist</th> <th>Genre</th> <th>Venue</th> <th>Date</th> <th>Event</th> </tr>";
            while ($stmtArtist->fetch()) { 
    
                $timestampDate = strtotime($eventdate);
                $displayDate = date("D d M Y", $timestampDate);
    
                echo "<tr> <td>$artist</td> <td>$genre</td> <td>$venue</td> <td>$eventdate</td> <td>$event</td></tr>";
    
            }
            echo "</table>";
        }
    }
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)
编辑
预览

报告相同问题?

手机看
程序员都在用的中文IT技术交流社区

程序员都在用的中文IT技术交流社区

专业的中文 IT 技术社区,与千万技术人共成长

专业的中文 IT 技术社区,与千万技术人共成长

关注【CSDN】视频号,行业资讯、技术分享精彩不断,直播好礼送不停!

关注【CSDN】视频号,行业资讯、技术分享精彩不断,直播好礼送不停!

客服 返回
顶部