dougu3290 2014-03-31 14:48
浏览 67
已采纳

PHP - 来自mysql的json_decode

I have an Android app, PHP page and MySql db.
The android app send a string parameter to the server, I use Gson so I know that the Json string is correct.
On server side I store that string of json as Text field.
On web client I take that field from my database and doing json_decode and receives a NULL.
Most of the site written by PHPMAKER 10 so I use it's database connection.

$result="";
$rs->MoveFirst();
if ($rs) {
    $result = $rs->fields[0];
}
$rs->Close();
$extras = json_decode($result, true);

I checked that json in Json validator and it looks fine.

Any ideas why I gets null? (maybe encoding)

EDIT: I did the following check:

echo "<script> var x = {$result}; console.log(x.length)</script>";

Chrome gave the following error:

Uncaught SyntaxError: Unexpected token ILLEGAL 

EDIT 2: If I print that string echo $result and copy that to a variable it works.

  • 写回答

2条回答 默认 最新

  • 「已注销」 2014-04-02 08:13
    关注

    I soled the problem:
    My json contained breaklines '/r' and '/r/n'.
    After removing them everything was fine.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥100 需要跳转番茄畅听app的adb命令
  • ¥50 寻找一位有逆向游戏盾sdk 应用程序经验的技术
  • ¥15 请问有用MZmine处理 “Waters SYNAPT G2-Si QTOF质谱仪在MSE模式下采集的非靶向数据” 的分析教程吗
  • ¥50 opencv4nodejs 如何安装
  • ¥15 adb push异常 adb: error: 1409-byte write failed: Invalid argument
  • ¥15 nginx反向代理获取ip,java获取真实ip
  • ¥15 eda:门禁系统设计
  • ¥50 如何使用js去调用vscode-js-debugger的方法去调试网页
  • ¥15 376.1电表主站通信协议下发指令全被否认问题
  • ¥15 物体双站RCS和其组成阵列后的双站RCS关系验证