求解答，急，本人真的是没有办法了

Question

本人可能没有学习Python的天赋，想半天也不能达到完美，仅需要第二问，比较基础的一个程序，请高抬贵手，解答完美可追加赏金
12月1日12：00截止哦

Answer 1

# 1

rabis = []
for i in range(2):
    rabi = input(f'请输入第{i+1}只兔子的名字：')
    rabis.append(rabi)
print(f"My rabbits' name are {rabis[0]} and {rabis[1]}")
fish = {}
count = input(f'请输入你有几条红色的鱼：')
fish['red'] = int(count)
count = input(f'请输入你有几条蓝色的鱼：')
fish['blue'] = int(count)
print(f'I have {fish["red"]} red finish and {fish["blue"]} blue fish.')


# 2
def pet(food1,food2,food3=None):
    if food3 != 'water':
        print('I need some water for pets')
    else:
        food = ['carrot' , 'vegetable' , 'water']
        print("There are3 kind of food for pet, the food list is:")
        print("------ {}".format(food1))
        print("------ {}".format(food2))
        print("------ {}".format(food3))
        return(food)

pet('carrot' , 'vegetable')
pet('carrot' , 'vegetable' , 'water')

# 3
food_label = {'food1':'carrot',"food2":'vegetable','food3':'water'}
food_label['food1'] = 'grass'
food_label['food4'] = 'snack'

for i, name in food_label.items():
    print('{} is {}'.format(i , name))