定义一个函数，实现“三数取中”

Question

问题遇到的现象和发生背景

用代码块功能插入代码，请勿粘贴截图

def quickSort(alist):
   quickSortHelper(alist,0,len(alist)-1)

def quickSortHelper(alist,first,last):
   if first<last:

       splitpoint = partition(alist,first,last)

       quickSortHelper(alist,first,splitpoint-1)
       quickSortHelper(alist,splitpoint+1,last)


def partition(alist,first,last):
   pivotvalue = alist[first]

   leftmark = first+1
   rightmark = last

   done = False
   while not done:

       while leftmark <= rightmark and \
               alist[leftmark] <= pivotvalue:
           leftmark = leftmark + 1

       while alist[rightmark] >= pivotvalue and \
               rightmark >= leftmark:
           rightmark = rightmark -1

       if rightmark < leftmark:
           done = True
       else:
           temp = alist[leftmark]
           alist[leftmark] = alist[rightmark]
           alist[rightmark] = temp

   temp = alist[first]
   alist[first] = alist[rightmark]
   alist[rightmark] = temp


   return rightmark
   
alist = [54,26,93,17,77,31,44,55,20]
quickSort(alist)
print(alist)

运行结果及报错内容

我的解答思路和尝试过的方法 已定义函数，下面不知道怎么做

我想要达到的结果 定义一个函数，实现“三数取中”

Answer 1

def quick_sort(array, l, r):
    if l < r:
        q = partition(array, l, r)
        quick_sort(array, l, q - 1)
        quick_sort(array, q + 1, r)
 
def partition(array, l, r):
    x = array[r]
    i = l - 1
    for j in range(l, r):
        if array[j] <= x:
            i += 1
            array[i], array[j] = array[j], array[i]
    array[i + 1], array[r] = array[r], array[i+1]
    return i+1