dtu15253 2017-09-04 08:45
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当此字符串也是字符串变量时,如何为字符串中的变量赋值?

I am having a variable $query1 and in this, I have a query string and in this query string, I have used another variable $sORp. The main problem is that I want to give this $sORp variable a value at runtime without changing my string variable holding the query. Is this possible?

Code Snippet is as below(dummy example):

$query1="SELECT $sORP,name from table1 
    where $sORp=:SRC_NAME 
    group by $sORp,name 
    order by $sORp";

I want to assign this variable $sORp "SRC" and "POOL" at run time as I don't want to write query twice with different values.

Use in code:

$sORp='SRC';
$sql=$query1;
$sth = oci_parse($con,$sql);

And this is not working, Is there any solution for this.

And on running this PHP file the error is: ORA-00936: missing expression

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3条回答 默认 最新

  • dousi2029 2017-09-04 08:52
    关注

    You cannot do this in this scripting language. $sql must be defined after $sORp .

    $sORp='SRC';
    $sth = oci_parse($con,"SELECT $sORP,name from table1 
                            where $sORp=:SRC_NAME 
                         group by $sORp,name 
                         order by $sORp");
    

    If you want your can create a function which will generate the right query on will:;

    function foo($sORp) {
      $retVal="SELECT $sORP,name from table1 
                 where $sORp=:SRC_NAME 
              group by $sORp,name 
              order by $sORp";
      return $retVal;
    }
    
    $sth = oci_parse($con,foo($sORp));
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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