检索PHP --with-config-file-scan-dir开关的值

Question

I need to return the path of folder configured via the --with-config-file-scan-dir switch for a particular PHP implementation.

I can achieve this by writing bash code something like:

folder=$(php --ini                                         \
        | grep "Scan for additional .ini files in:"        \
        | cut -d" " -f7       \
        )

But the above approach seems inexact and potentially error prone.

My preference would be to do something like the following:

folder=$(php -r 'print ini_get("with-config-file-scan-dir config option");')

but I can't seem to find the necessary configuration option name.

I would greatly appreciate some guru input on this if you have it!

thanks in advance

Answer 1

You can use PHP_CONFIG_FILE_SCAN_DIR.

php -r "echo PHP_CONFIG_FILE_SCAN_DIR;"