我正在使用以下表达式查找 我希望它返回6 但它只返回 这是 有什么方法可以得到'和<的出现次数 代码>“在一个字符串中我不希望计数包含 \'或 \”。
$ subStr ='asdf“asdf”“a \\”sdf \'asdf \'\'a \\\'sdf';
npreg_match_all（'/ [^ \\\\] \'| [^ \ \\\] \“/'，$ subStr，$ matches）;
echo count（$ matches [0]）;
4 。我认为这是因为字符串“”和''只计算一次。
$ matches 包含：
Array
（
[0] =＆gt; Array
（\ n [0] =＆gt; f“
[1] =＆gt; f”
[2] =＆gt; f'
[3] =＆gt; f'
）
）
< / code>
6 的数量吗？注意我还需要排除 \“ 和 \'。
I'm using the following expression to find the number of occurences of ' and " in a string I don't want the count to include \' or \".
$subStr = 'asdf"asdf""a\\"sdf\'asdf\'\'a\\\'sdf';
preg_match_all('/[^\\\\]\'|[^\\\\]\"/', $subStr, $matches);
echo count($matches[0]);
I expect it to return 6 but it only returns 4. I think this is because the strings "" and '' are only count once.
This is what $matches contain:
Array
(
[0] => Array
(
[0] => f"
[1] => f"
[2] => f'
[3] => f'
)
)
Is there any way I can get the count of 6? Note that I also need to exclude the \" and \'.
微信扫一扫
