正则表达式替换在线组后的所有空格

Question

Okay... that question sounds strange, but what I mean is this:

I have a specific group to search for, and I want every space AFTER that group, but only on the current line, to be stripped out. My specific example is this:

@subpackage Some Word Stuff

@subpackage does not accept whitespace, but I didn't know that at the time, and I have many many of these lines to fix. I'd like to do a find and replace with regex (my IDE supports this) to strip out the white spaces between the words after EVERY instance of @subpackage.

EDIT: Clarity by example perhaps

"@subpackage Some Word Stuff" -> "@subpackage SomeWordStuff"

Answer 1

Find using below regex, replace with empty string '' .
(Just use replace_all)

 # '~(?mi-)(?:(?!\A)\G|^@subpackage)[^ 
]*\K[ ]+~'

 (?xmi-)                     # Inline 'Expanded, multiline, case insensitive' modifiers
 (?:
      (?! \A )                    # Matched before, start from here
      \G                          
   |                            # or,
      ^ @subpackage               # '@Subpackage' at bol (remove '^' if not at bol)
 )
 [^ 
]*                   # Not space or line breaks
 \K                          # Don't include anything from here back in match
 [ ]+                        # 1 or more spaces

Here is one for all non-linebreak whitespace.

 # '~(?mi-)(?:(?!\A)\G|^@subpackage)\S*\K[^\S
]+~'

 (?xmi-)                     # Inline 'Expanded, multiline, case insensitive' modifiers
 (?:
      (?! \A )                    # Matched before, start from here
      \G                          
   |                            # or,
      ^ @subpackage               # '@Subpackage' at bol (remove '^' if not at bol)
 )
 \S*                         # 0 or more, Not whitespace
 \K                          # Don't include anything from here back in match
 [^\S
]+                  # 1 or more non-linebreak whitespaces