SpringBootJPA 多对多死循环

Question

@DynamicInsert
@DynamicUpdate
@Builder
@Entity
@Data //生成getter,setter等函数
@AllArgsConstructor //生成全参数构造函数
@NoArgsConstructor //生成无参构造函数
@SuppressWarnings("unused")//去除黄色警告
@Table(name = "cs_album")
public class CsAlbum {

// 主键ID
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @ApiModelProperty(name = "id", value = "主键ID",hidden = true)
    private Long id;


    //用户id
    @Column(nullable=false,name="uId",columnDefinition="bigint COMMENT '用户id'")
    @ApiModelProperty(name = "uId", value = "用户id")
    private Long  uId;

        @ManyToMany
    @JoinTable(
            //指定表名字
            name = "cs_album_design_works",
            //配置维护放字段
            joinColumns = @JoinColumn(name = "album_id",referencedColumnName = "id"),
            //配置被维护放字段
            inverseJoinColumns = @JoinColumn(name = "design_works_id",referencedColumnName = "id")
    )
    private List<CsDesignWorks> csDesignWorks = new ArrayList<>(  );



}

被维护表CsDesignWorks

@DynamicInsert
@DynamicUpdate
@Builder
@Entity
@Data //生成getter,setter等函数
@AllArgsConstructor //生成全参数构造函数
@NoArgsConstructor //生成无参构造函数
@SuppressWarnings("unused")//去除黄色警告
@Table(name = "cs_design_works")
public class CsDesignWorks {    

    // 主键ID
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @ApiModelProperty(name = "id", value = "主键ID",hidden = true)
    private Long id;



    @ManyToMany(mappedBy = "csDesignWorks")
    private List<CsAlbum> csAlbums = new ArrayList<>(  );





}

Service类

@Service
@Transactional
public class CsAlbumServiceImpl implements CsAlbumService {
//根据id查询专辑内容
    @Override
    public CsAlbum viewAlbum(Long id){
        CsAlbum csAlbum = csAlbumRepository.findById( id ).get();
        csAlbum.getCsDesignWorks();

        return  csAlbum;

    }
            }

出现死循环为什么呢

Answer 1

你的循环错误，能发出来不？部分的，试试在@manytomany 字段加@J
sonIgnore，或者加@JsonIgnoreProperties(value = { "实体对象" })
死循环错误能给出吗？多对一，多对多，死循环大多是序列化问题

Answer 2

https://blog.csdn.net/sinat_32023305/article/details/86066751

Answer 3

大哥不要jpa还要问这样的问题，我们开发中禁止使用oneToOne 和 ManyToOne，OneToMany