duanlongling5308 2014-12-09 05:26 采纳率: 0%
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如何在Input :: all()中获取数组数据并将其作为hasMany()关系存储到实际记录中?

I am working on a project and there is a table diagnostic. There is another table diagnostic_detail. diagnostic has a one to many relation with diagnostic_detail. The post data coming in the Diagnostic controller to make a new record has all the information about the diagnostic itself and an array of details to be pushed into the diagnostic_detail method.

Now it is simple to create the diagnostic record:

Diagnostic::create(Input::all());

But how do I take all the data for the detail and create it?

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  • dongyuans61046 2014-12-09 07:25
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    You'll have to loop and create the detail object manually. Try this:

    $details = array();
    foreach(Input::get('diagnostic_detail') as $detail){
        $details[] = new DiagnosticDetail($detail);
    }
    $diagnostic->details()->saveMany($details);
    

    In this example, DiagnosticDetail is the model that is referenced by hasMany() and details is the hasMany relationship.

    More information on inserting related models

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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