c语言syntax error :'type'报错

Question

求问此处为什么有 syntax error :'type'报错？
此问题源于C Primer Plus第八章练习题第五题：使用更智能的猜测策略，使程序可以猜出1-100内的任意一个整数。

如：程序最初猜50，询问用户是猜大了、猜小了还是猜对了。如果猜小了，那么下一次猜测的值应是50和100中值，耶尔就是75。如果这次猜大了，那么下一次猜测的值应是50和75的中值，等等。使用二分查找（binary search）策略，如果用户没有欺骗程序，那么程序很快就会猜到正确的答案

#include<stdio.h>
char get_choice(void);
char get_first(void);
int main()
{
    int head=1;
    int tail=100;
    int guess=(head+tail)/2;
    char ch;
    printf("I will guess an integer from 1 to 100.\n");
    printf("Please responde by Biger(B) or Lower(L) or Yes(Y).\n");
    do
    {
        printf("Is your number is %d?\n",guess);
        if((ch=get_choice())=='Y')
            break;
        if((ch=get_choice())=='B')
        {
            tail=guess-1;
            guess=(head+tail)/2;
            continue;
        }
        else if((ch=get_choice())=='L')
        {
            head=guess+1;
            guess=(head+tail)/2;
            continue;
        }
        while((ch=get_choice())!='Y');

        printf("I know the answer!\n");
        return 0;
}

char get_choice(void)
{
    int ch;
    ch=get_first();
    while(ch!='B'&&ch!='L'&&ch!='Y')
    {
        printf("I can only know Biger or Lower or Yes.\n");
        printf("Please try again!\n");
        ch=get_first();
    }
    return ch;
}

char get_first()
{
    int ch;
    ch=getchar();
    while(getchar()!='\n')
        continue;
    return ch;
}

在VC++6.0运行后会在第35行 char get_choice(void)处报错syntax error:'type'。想求问一下为什么会有这个报错？谢谢！

Answer 1

定义的两个函数不用加void，还有一些其他的错误都改好了，望采纳回答

#include<stdio.h>
char get_first()
{
    int ch;
    ch=getchar();
    while(getchar()!='\n')
        continue;
    return ch;
}
char get_choice()
{
    int ch;
    ch=get_first();
    while(ch!='B'&&ch!='L'&&ch!='Y')
    {
        printf("I can only know Biger or Lower or Yes.\n");
        printf("Please try again!\n");
        ch=get_first();
    }
    return ch;
}


int main()
{
    int head=1;
    int tail=100;
    int guess=(head+tail)/2;
    char ch;
    printf("I will guess an integer from 1 to 100.\n");
    printf("Please responde by Biger(B) or Lower(L) or Yes(Y).\n");
    do
    {
        printf("Is your number is %d?\n",guess);
        ch=get_choice();
        if(ch=='Y')
            break;
        if(ch=='B')
        {
            tail=guess-1;
            guess=(head+tail)/2;
            continue;
        }
        else if(ch=='L')
        {
            head=guess+1;
            guess=(head+tail)/2;
            continue;
    }}
        while(ch!='Y');

        printf("I know the answer!\n");
        return 0;
}