accumulate算法可以将string类的容器中的元素相加吗

Question

accumulate算法可以将string类的容器中的元素相加吗
如果可以该怎么编写呢

vector<string>v;
    v.push_back("a");
    v.push_back("b");
    v.push_back("c");
    cout<<accumulate(v.begin(),v.end(),"hello");

Answer 1

#include <iostream>
#include <vector>
#include <numeric>

using namespace std;

int main() {
    vector<string> words{"this ", "is ", "a ", "sentence!"};
    string init, res;
    res = accumulate(words.begin(), words.end(), init);    // 连接字符串
    cout << res << endl;    // this is a sentence!
    return 0;
}