这个代码怎么去理解呢

Question

 unsigned int Checksum(void* buf, int iBufLen, CHECKSUM iType)
{
    unsigned char* newbuf8;
    unsigned short* newbuf16;
    unsigned int sum = 0;
    unsigned int checksum = 0;

    switch (iType)
    {
    case CHK_16BIT:
    {
        newbuf16 = (unsigned short*)buf;
        for (int i = 0; i < iBufLen; i++)
        {
            sum = sum + *newbuf16;
            newbuf16++;
        }
        checksum = sum % (0xFFFF + 0x0001);
        return checksum;
        break;
    }
    case CHK_8BIT:
    {
        newbuf8 = (unsigned char*)buf;
        for (int i = 0; i < iBufLen; i++)
        {
            sum = sum + *newbuf8;
            newbuf8++;
        }
        checksum = sum % (0xFF + 0x01);
        return checksum;
        break;
    }
    default:
    {
        break;
    }
    };

}
这个是他的输出

Answer 1

判断一个数是8bit还是16bit?
函数中主要还是需要理解swich每个分支的处理过程，实际上呢两个处理大同小异，都是遍历求和(指针直接++可以表示数组后移)，然后根据bit数取余返回。
8bit数据最大为0xff,加1取余即可获取相应8bit数据
16bit数据类似