php如何判断3个并输出

Question

怎么把下面js写成api，请求方式 https://域名/api.php?qq=123456
访问后判断系统，安卓 苹果 pc电脑 跳转域名不同，然后跳转QQ api.php?qq=123456

<script type="text/javascript">
if(/Android/i.test(navigator.userAgent)) {
window.location.href = "https://wpa.qq.com跳转域名不同/msgrd?v=3&uin=".$_GET['这是QQ']."&site=qq&menu=yes";
}
if(/iPhone|/i.test(navigator.userAgent)) {
window.location.href = "https://wpa.qq.com跳转域名不同/msgrd?v=3&uin=".$_GET['这是QQ']."&site=qq&menu=yes";
}
if(/window/i.test(navigator.userAgent)) {
window.location.href = "https://wpa.qq.com跳转域名不同/msgrd?v=3&uin=".$_GET['这是QQ']."&site=qq&menu=yes";
}
<script>

Answer 1

在 PHP 中实现上述功能

<?php
$qq = $_GET['qq'];
$user_agent = $_SERVER['HTTP_USER_AGENT'];

if (preg_match('/Android/i', $user_agent)) {
    header("Location: https://wpa.qq.com/android_domain?v=3&uin=$qq&site=qq&menu=yes");
} elseif (preg_match('/iPhone/i', $user_agent)) {
    header("Location: https://wpa.qq.com/iphone_domain?v=3&uin=$qq&site=qq&menu=yes");
} else {
    header("Location: https://wpa.qq.com/pc_domain?v=3&uin=$qq&site=qq&menu=yes");
}