关于#JS#的问题，如何解决？

Question

根据arr数组的顺序，把init里面的对象按照arr的顺序放，得出arr3数组

     const arr = ['operation', 'age', 'name', 'address'];
        const init = [{
            title: 'name',
            dataIndex: 'name',
            width: '25%',
        }, {
            title: 'age',
            dataIndex: 'age',
            width: '15%',
        }, {
            title: 'address',
            dataIndex: 'address',
            width: '40%',
        }, {
            title: 'operation',
            dataIndex: 'operation',
        }]
        let arr3 = [{
            title: 'operation',
            dataIndex: 'operation',
        }, {
            title: 'age',
            dataIndex: 'age',
            width: '15%',
        }, {
            title: 'name',
            dataIndex: 'name',
            width: '25%',
        }, {
            title: 'address',
            dataIndex: 'address',
            width: '40%',
        }, ];

Answer 1

用数组sort下就行，排序回调中的2个a，b参数，分别找dataIndex在arr中的下标，升序用aIndex-bIndex，降序则bIndex-aIndex

    const arr = ['operation', 'age', 'name', 'address'];
    const init = [{
        title: 'name',
        dataIndex: 'name',
        width: '25%',
    }, {
        title: 'age',
        dataIndex: 'age',
        width: '15%',
    }, {
        title: 'address',
        dataIndex: 'address',
        width: '40%',
    }, {
        title: 'operation',
        dataIndex: 'operation',
        }]

    let arr3 = JSON.parse(JSON.stringify(init)).sort(function (a, b) {
        var aIndex = arr.findIndex(i => a.dataIndex == i);
        var bIndex = arr.findIndex(i => b.dataIndex == i);

        return aIndex - bIndex;
    })
    console.log(arr3)