dtmjqyfz21793 2015-12-01 10:29
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jquery ajax请求多个返回值?

I followed the tutorial from this page:

http://www.keyboardninja.eu/webdevelopment/jquery-ajax-call-tutorial

and already got the random number output. But how can I change the function (and the php file?), that I get multiple returns ("msg" in the example), to fill different divs? Or is that not possible, so I gotta fill the containing div with the stuff and put a whole lot of code into the echo part in the php file?

Thanks

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  • dpcyx08288 2015-12-01 10:37
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    in process.php file, add all messages in array than convert into json , as given below.

    $msg=array();
    $msg[]  = $msg1;
    $msg[]  = $msg2;
    .
    .
    ........
    
    echo json_encode($msg);
    

    now process json in your ajax call to show all of your message using each in javascript

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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