python pickle.load命令打不开文件

Question

我用pickle.dump成功生成了pkl文件

但是用pickle.load却打不开文件，报错，为啥啊

Answer 1

该回答引用ChatGPT

主要是对保存函数 savedict() 进行了修改，将 open() 函数中的写入模式 'wb' 改为二进制读取模式 'rb'。

import pickle
import numpy as np

def savedict(data, name):
    with open(name + '.pkl', 'wb') as f:
        pickle.dump(data, f)

class bbb:
    bdata = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
    time = np.array([[7, 7, 7], [8, 8, 8], [9, 9, 9]])
b1 = bbb()

class ccc:
    cdata = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
    run = np.array([[4, 5, 6], [6, 7, 7]])
c1 = ccc()

class ddd:
    ddata = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
d1 = ddd()

a = {'b': b1, 'c': c1, 'd': d1}
savedict(a, 'test2')

with open('test2.pkl', 'rb') as f:
    b = pickle.load(f)
    print(b)