如何在arr数组中找到与arr_1相同的对象

Question

如何在arr数组中找到与arr_1相同的对象

let arr = [{
            "id": 41,
            "name": "详情一",
            "details": [{
                "index": 1,
                "name": "皮皮",
                "age": 32,
                "address": '南京市'
            }, {
                "index": 1,
                "name": "悠悠",
                "age": 33,
                "address": '琼海市'
            }, {
                "index": 2,
                "name": "涛涛",
                "age": 23,
                "address": '杭州市'
            }, {
                "index": 1,
                "name": "赵三",
                "age": 42,
                "address": '琼海市'
            }, {
                "index": 1,
                "name": "八八",
                "age": 21,
                "address": '北京市'
            }]
        }, {
            "id": 43,
            "name": "详情二",
            "details": [{
                "index": 1,
                "name": "张三",
                "age": 12,
                "address": '上海市'
            }, {
                "index": 1,
                "name": "李四",
                "age": 33,
                "address": '杭州市'
            }, {
                "index": 1,
                "name": "王五",
                "age": 21,
                "address": '南昌市'
            }, {
                "index": 1,
                "name": "赵六",
                "age": 32,
                "address": '南京市'
            }]
        }]

        let arr_1 = [{
            "index": 1,
            "name": "张三",
            "age": 12,
            "address": '上海市浦东新区'
        }, {
            "index": 1,
            "name": "李四",
            "age": 33,
            "address": '杭州市'
        }, {
            "index": 1,
            "name": "王五",
            "age": 21,
            "address": '南昌市'
        }, {
            "index": 1,
            "name": "赵六",
            "age": 32,
            "address": '南京市'
        }]

Answer 1

不知道具体是要实现什么效果，下面是将arr_1中项在arr 第几项和details中位置打印出来

<script>

    let arr = [{
        "id": 41,
        "name": "详情一",
        "details": [{
            "index": 1,
            "name": "皮皮",
            "age": 32,
            "address": '南京市'
        }, {
            "index": 1,
            "name": "悠悠",
            "age": 33,
            "address": '琼海市'
        }, {
            "index": 2,
            "name": "涛涛",
            "age": 23,
            "address": '杭州市'
        }, {
            "index": 1,
            "name": "赵三",
            "age": 42,
            "address": '琼海市'
        }, {
            "index": 1,
            "name": "八八",
            "age": 21,
            "address": '北京市'
        }]
    }, {
        "id": 43,
        "name": "详情二",
        "details": [{
            "index": 1,
            "name": "张三",
            "age": 12,
            "address": '上海市'
        }, {
            "index": 1,
            "name": "李四",
            "age": 33,
            "address": '杭州市'
        }, {
            "index": 1,
            "name": "王五",
            "age": 21,
            "address": '南昌市'
        }, {
            "index": 1,
            "name": "赵六",
            "age": 32,
            "address": '南京市'
        }]
    }]

    let arr_1 = [{
        "index": 1,
        "name": "张三",
        "age": 12,
        "address": '上海市浦东新区'
    }, {
        "index": 1,
        "name": "李四",
        "age": 33,
        "address": '杭州市'
    }, {
        "index": 1,
        "name": "王五",
        "age": 21,
        "address": '南昌市'
    }, {
        "index": 1,
        "name": "赵六",
        "age": 32,
        "address": '南京市'
        }]

    let result = [];
    arr_1.forEach((i, iIndex) => {
        arr.forEach((j, jIndex) => {
            var index = j.details.findIndex(k => k.name == i.name && k.age == i.age && k.address == i.address);//根据name，age，address一样判断为同一个人
            if (index != -1) {
                result.push(`arr_1第${iIndex + 1}项${i.name}出现在arr第${jIndex + 1}项的details数组第${index + 1}项中`)
            }
        })
    });
    console.log(result)
</script>